Dado un número N. La tarea es escribir un programa para encontrar el N-ésimo término de la siguiente serie:
0, 7, 18, 33, 51, 75, 102, 133, …(Términos N)
Ejemplos:
Input: N = 4 Output: 33 For N = 4 4th Term = ( 2 * 4 * 4 + 4 - 3) = 33 Input: N = 10 Output: 206
Enfoque: El enésimo término generalizado de esta serie:
A continuación se muestra la implementación requerida:
C++
// C++ program to find the N-th term of the series: // 0, 7, 18, 33, 51, 75, 102, ..... #include <iostream> #include <math.h> using namespace std; // calculate Nth term of series int nthTerm(int n) { return 2 * pow(n, 2) + n - 3; } // Driver code int main() { int N = 4; cout << nthTerm(N) << endl; return 0; }
Java
// Java program to find the N-th term of the series: // 0, 7, 18, 33, 51, 75, 102, ..... import java.io.*; class GFG { // calculate Nth term of series static int nthTerm(int n) { return 2 * (int)Math.pow(n, 2) + n - 3; } // Driver code public static void main (String[] args) { int N = 4; System.out.println( nthTerm(N)); } } // This code is contributed // by anuj_67..
Python3
# Python3 program to find the # N-th term of the series: # 0, 7, 18, 33, 51, 75, 102, ..... # calculate Nth term of series def nthTerm(n): return 2 * pow(n, 2) + n - 3 # Driver code N = 4 print(nthTerm(N)) # This code is contributed by # Sanjit_Prasad
C#
// C# program to find the // N-th term of the series: // 0, 7, 18, 33, 51, 75, 102, ..... using System; class GFG { // calculate Nth term of series static int nthTerm(int n) { return 2 * (int)Math.Pow(n, 2) + n - 3; } // Driver code public static void Main () { int N = 4; Console.Write( nthTerm(N)); } } // This code is contributed // by ChitraNayal
PHP
<?php // PHP program to find the // N-th term of the series: // 0, 7, 18, 33, 51, 75, 102,... // calculate Nth term of series function nthTerm($n) { return 2 * pow($n, 2) + $n - 3; } // Driver code $N = 4; echo nthTerm($N) + "\n"; // This code is contributed // by Akanksha Rai(Abby_akku) ?>
Javascript
<script> // JavaScript program to find the N-th term of the series: // 0, 7, 18, 33, 51, 75, 102, ..... // calculate Nth term of series function nthTerm( n) { return 2 * Math.pow(n, 2) + n - 3; } // Driver code let N = 4; document.write( nthTerm(N) ); // This code contributed by gauravrajput1 </script>
Producción:
33
Complejidad de tiempo: O(1)
Espacio Auxiliar : O(1) ya que usa variables constantes